If it's not what You are looking for type in the equation solver your own equation and let us solve it.
2v^2-2v-40=0
a = 2; b = -2; c = -40;
Δ = b2-4ac
Δ = -22-4·2·(-40)
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{324}=18$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-18}{2*2}=\frac{-16}{4} =-4 $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+18}{2*2}=\frac{20}{4} =5 $
| 2(-6x-8)=32 | | x-7+7(x-1)=-10(2-x)+x+12(x+1) | | -8=x^2-8x | | -2x-2(-8)=16 | | 7x=4+10 | | 2(5x+7)=44 | | x*2.4= | | 12k2-8k-24=0 | | 6x-(9-3x-12=0 | | (3x-7)-(5x+12)=0* | | 5x=19x-99 | | 19x-99=5x | | -2y=-3y-20 | | 2x+7-8x+5-13=14-6x-2-3x | | 2=4t+6 | | 3(2x-4)=9-3(x=1) | | k-10=4 | | ^7-6x=x | | 5(x−9)=−5 | | 24=v•3 | | (9x+3)+(5x+7)=3+(x-1) | | .75 x+2=1.25 x−6 | | (x/100)x560=280 | | 8p-1=63 | | 2X3(2x/7)=30 | | 43x+2=45x−6 | | (9x+3)-(5x+7)=3+(x-1) | | 21-3k=k-10 | | 90+48=180-x | | 43 x+2=45 x−6 | | 3(a+7=-33 | | r=9.8 |